document.write( "Question 859316: Martha lived the first one-quarter of her life unmarried, the next one-half of her life in her first marriage, the next one-sixth of her life in her second marriage, and her final 8 years as a widow. how old was she when she died?\r
\n" ); document.write( "\n" ); document.write( "solution is 96. i need you to workout? :)
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Algebra.Com's Answer #517762 by ankor@dixie-net.com(22740)\"\" \"About 
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Martha lived the first one-quarter of her life unmarried, the next one-half of her life in her first marriage, the next one-sixth of her life in her second marriage, and her final 8 years as a widow.
\n" ); document.write( " how old was she when she died?
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\n" ); document.write( "Let a = her age when she died
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\n" ); document.write( "Write a equation for each statement
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\n" ); document.write( "\"Martha lived the first one-quarter of her life unmarried,
\n" ); document.write( "\"1%2F4\"a = unmarried yrs
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\n" ); document.write( " the next one-half of her life in her first marriage,\r
\n" ); document.write( "\n" ); document.write( "\"1%2F2\"a = her first marriage yrs
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\n" ); document.write( "the next one-sixth of her life in her second marriage,\r
\n" ); document.write( "\n" ); document.write( "\"1%2F6\"a = 2nd marriage yrs
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\n" ); document.write( "and her final 8 years as a widow.
\n" ); document.write( "a = \"1%2F4\"a + \"1%2F2\"a + \"1%2F6\"a + 8
\n" ); document.write( "common denominator is 12
\n" ); document.write( "a = \"3%2F12\"a + \"6%2F12\" + \"2%2F12\"a + 8
\n" ); document.write( "a = \"11%2F12\"a + 8
\n" ); document.write( "a - \"11%2F12\"a = 8
\n" ); document.write( "\"1%2F12\"a = 8
\n" ); document.write( "a = 12 * 8
\n" ); document.write( "a = 96 yrs \r
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