document.write( "Question 72434: Bob paid for his breakfast with 36 coins consisting of dimes and quarters. if the bill was 4.50 then how amny of each type of coin did he use. \n" ); document.write( "
Algebra.Com's Answer #51775 by Edwin McCravy(20056)\"\" \"About 
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Bob paid for his breakfast with 36 coins \r\n" );
document.write( "consisting of dimes and quarters. if the bill \r\n" );
document.write( "was 4.50 then how amny of each type of coin \r\n" );
document.write( "did he use.\r\n" );
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document.write( "Two ways to solve.  Use whichever one you are\r\n" );
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document.write( "Method 1. Using one unknown\r\n" );
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document.write( "Let Q = the number of quarters.\r\n" );
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document.write( "Then to find the number of dimes, use the formula\r\n" );
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document.write( "(SECOND NUMBER) = (TOTAL OF BOTH NUMBERS) — (FIRST NUMBER)\r\n" );
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document.write( "so\r\n" );
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document.write( "NUMBER OF DIMES = 36 - Q\r\n" );
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document.write( "The value of all the quarters = .25Q\r\n" );
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document.write( "The value of all the dimes = .10(36 — Q)\r\n" );
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document.write( "Value of quarters + Value of dimes = $4.50 \r\n" );
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document.write( "                .25Q + .10(36 — Q) = 4.50\r\n" );
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document.write( "Solve that for Q and get Q = 6, then use\r\n" );
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document.write( "NUMBER OF DIMES = 36 - Q = 36 - 6 = 30\r\n" );
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document.write( "So the answer is 6 quarters and 20 dimes.\r\n" );
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document.write( "Method 2. Using two unknowns:\r\n" );
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document.write( "          D + Q = 36\r\n" );
document.write( "    .10D + .25Q = 4.50\r\n" );
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document.write( "Solve that system and get D = 30, Q = 6\r\n" );
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document.write( "Edwin
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