document.write( "Question 859379: The base of a parallelogram and a triangle are the same length, and both figures have the same area. What is true about height of the triangle?
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Algebra.Com's Answer #517739 by Awesom3guy(31)\"\" \"About 
You can put this solution on YOUR website!
When you are having trouble with this, it helps when you draw it.
\n" ); document.write( "Let's call the height of the parallelogram p and the one of the triangle t.\r
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\n" ); document.write( "\n" ); document.write( "Both of their bases are the same length. Let's call that B.\r
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\n" ); document.write( "\n" ); document.write( "The area of a parallelogram is base*height, and of the triangle is HALF of its own (base*height).\r
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\n" ); document.write( "\n" ); document.write( "The two areas are the same, and so are the bases, and what is different are the heights. So you set up:\r
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\n" ); document.write( "\n" ); document.write( "\"B%2Ap+=+B%2At%2F2\"
\n" ); document.write( "As B can be cancelled (same value on numerators on both sides, you have this:\r
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\n" ); document.write( "\n" ); document.write( "\"p+=+t%2F2\"
\n" ); document.write( "So we can say that - height of the parallelogram is half of the one of triangle, or, if we multiply the equation with 2
\n" ); document.write( "\"t+=+2p\"
\n" ); document.write( "Height of the triangle is double the height of the parallelogram.
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