document.write( "Question 859408: How do I convert y=-2(x-2)^2 into standard form? \n" ); document.write( "
Algebra.Com's Answer #517735 by Awesom3guy(31)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"y=-2%2A%28x-2%29%5E2\"
\n" ); document.write( "First you simplify, i.e. square the expression in the bracket.
\n" ); document.write( "\"y+=+-2%2A%28+%28x-2%29%2A%28x-2%29+%29\"\r
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\n" ); document.write( "\n" ); document.write( "FOIL:
\n" ); document.write( "\"y+=+-2%2A%28x%2Ax+-+2%2Ax+-+2%2Ax+%2B+2%2A2%29\"
\n" ); document.write( "\"y+=+-2%2A%28x%5E2+-+4x+%2B+4%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now you expand the bracket (multiply everything with -2):
\n" ); document.write( "\"y+=+2x%5E2+%2B+8x+-+8\"\r
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\n" ); document.write( "\n" ); document.write( "That's it. The standard form of a curve is \"y+=+Ax%5E2+%2B+Bx+%2B+C\".
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