document.write( "Question 72450: Business and finance. The revenue for a sandwich shop is directly proportional to its advertising budget. When the owner spent $2000 a month on advertising, the revenue was $120,000. If the revenue is now $180,000, how much is the owner spending on advertising? \n" ); document.write( "
Algebra.Com's Answer #51772 by Edwin McCravy(20060)\"\" \"About 
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Business and finance. The revenue for a sandwich \r\n" );
document.write( "shop is directly proportional to its advertising \r\n" );
document.write( "budget. When the owner spent $2000 a month on \r\n" );
document.write( "advertising, the revenue was $120,000. If the \r\n" );
document.write( "revenue is now $180,000, how much is the owner \r\n" );
document.write( "spending on advertising.\r\n" );
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document.write( ">>...The revenue for a sandwich shop is directly \r\n" );
document.write( "proportional to its advertising budget...<<\r\n" );
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document.write( "The formula is \r\n" );
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document.write( "          R = kA\r\n" );
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document.write( ">>...When the owner spent $2000 a month on \r\n" );
document.write( "advertising, the revenue was $120,000...<<\r\n" );
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document.write( "Plug that in the formula:\r\n" );
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document.write( "      120000 = k(2000)\r\n" );
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document.write( "Solve that for k\r\n" );
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document.write( "      120000 = 2000k\r\n" );
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document.write( "Divide both sides by 2000\r\n" );
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document.write( "          60 = k\r\n" );
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document.write( "Now plug 60 for k in the formula:\r\n" );
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document.write( "          R = kA\r\n" );
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document.write( "          R = 60A\r\n" );
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document.write( "Now plug 180000 for R:\r\n" );
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document.write( "     180000 = 60A\r\n" );
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document.write( "Solve for A. Divide both sides by 60\r\n" );
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document.write( "       3000 = A\r\n" );
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document.write( "So the owner is now spending $3000 per month \r\n" );
document.write( "on advertising.\r\n" );
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document.write( "Edwin
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