document.write( "Question 859248: How can I solve this problem algebraically ln(x + 3) – ln(x – 4) = ln(x) \n" ); document.write( "
Algebra.Com's Answer #517658 by rothauserc(4718)\"\" \"About 
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ln(x + 3) – ln(x – 4) = ln(x)
\n" ); document.write( "ln [ (x+3) / (x-4) ] = ln(x)
\n" ); document.write( "ln [ (x+3) / (x-4) ] - ln(x) = 0
\n" ); document.write( "ln [ ((x+3) / (x-4)) / x ] = 0
\n" ); document.write( "ln [ (x+3) / x(x-4) ] = 0
\n" ); document.write( "now x cannot be less than or equal to 4 since ln is not defined for 0 or negative values,
\n" ); document.write( "therefore x must be greater than 4
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