document.write( "Question 859084: What is the solution to:
\n" ); document.write( "2x+y=6, 3x-2y=2 using substitution?
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Algebra.Com's Answer #517568 by Fombitz(32388)\"\" \"About 
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From eq. 1,
\n" ); document.write( "\"y=6-2x\"
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( "\"3x-2%286-2x%29=2\"
\n" ); document.write( "\"3x-12%2B4x=2\"
\n" ); document.write( "\"7x=14\"
\n" ); document.write( "\"x=2\"
\n" ); document.write( "Then,
\n" ); document.write( "\"y=6-2%282%29\"
\n" ); document.write( "\"y=6-4\"
\n" ); document.write( "\"y=2\"
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