document.write( "Question 72429: Adding and Subtracting Radical Expressions:\r
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\n" ); document.write( "\n" ); document.write( "\"+%285%29%2F%28x%2By%29+\" + \"+%285%29%2F%28x%5E2-y%5E2%29+\"
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Algebra.Com's Answer #51756 by bucky(2189)\"\" \"About 
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To simplify this expression, you can first note that \"x%5E2+-+y%5E2\" is the difference
\n" ); document.write( "of two squares. Therefore, it factors into \"%28x+-+y%29%2A+%28x+%2B+y%29\". Substitute these and
\n" ); document.write( "the problem becomes:
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\n" ); document.write( "\"+%285%29%2F%28x%2By%29+%2B+%285%29%2F%28%28x-y%29%2A%28x%2By%29%29\"
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\n" ); document.write( "Notice that the first fraction lacks a (x-y) term in the denominator. If it had one, then
\n" ); document.write( "this first fraction could be combined with the second fraction because they both would have
\n" ); document.write( "the same denominator.
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\n" ); document.write( "Let's multiply the first fraction by \"%28x-y%29%2F%28x-y%29\". Because the numerator is identical to
\n" ); document.write( "the denominator in this multiplier, it is equivalent to multiplying by 1. The multiplication
\n" ); document.write( "results in:
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\n" ); document.write( "Since the two fractions now have a common denominator of \"%28x-y%29%2A%28x%2By%29\" their numerators
\n" ); document.write( "may be put over this common denominator to get:
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\n" ); document.write( "\"%285%2A%28x-y%29%2B5%29%2F%28%28x-y%29%2A%28x%2By%29%29\"
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\n" ); document.write( "Then, doing the multiplication in the numerator results in:
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\n" ); document.write( "\"%285%2Ax+-+5%2Ay+%2B+5%29%2F%28%28x-y%29%2A%28x%2By%29%29\"
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\n" ); document.write( "And factoring the common 5 in the numerator:
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\n" ); document.write( "\"5%2A%28x+-+y+%2B1%29%2F%28%28x-y%29%2A%28x%2By%29%29\"
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\n" ); document.write( "Hope this gives you some additional insight into working with fractional expressions.
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