document.write( "Question 859014: Factorise each of the following as fully as possible.
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document.write( "-t*t + 11t - 24 \n" );
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Algebra.Com's Answer #517536 by Awesom3guy(31)![]() ![]() ![]() You can put this solution on YOUR website! -t^2 + 11t - 24 \n" ); document.write( "-1t^2 + 11t - 24 \n" ); document.write( "You \"break\" the middle term with the number and the variable into two terms. \n" ); document.write( "These two terms must add to make 11x. \n" ); document.write( "They also must multiply to make 24, which is the product of -1 from the t^2 and -24\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "These two numbers are 3 and 8 as 3+8=11 and 3*8=24. \n" ); document.write( "-t^2 + 3t + 8t - 24 \n" ); document.write( "Factor these two parts individually: \n" ); document.write( "(-t^2 + 3t) + (8t - 24) \n" ); document.write( "Like this: \n" ); document.write( "t*(-t + 3) + 8*(t - 3) \n" ); document.write( "The brackets must be completely equal. Here you must make the first \"t\" which multiplies the bracket negative, and the brackets will be equal: \n" ); document.write( "-t*(t - 3) + 8*(t - 3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now you can factor the part in the bracket and you're done. \n" ); document.write( "(t-3)*(-t+8) \n" ); document.write( " |