document.write( "Question 858924: A father has a son and a daughter. The father is five times old as the daughter and the son is 2 years older than the daughter. In 10 years, the sum of their three ages will be 81. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #517505 by ankor@dixie-net.com(22740)\"\" \"About 
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A father has a son and a daughter.
\n" ); document.write( " The father is five times old as the daughter and the son is 2 years older than the daughter.
\n" ); document.write( " In 10 years, the sum of their three ages will be 81.
\n" ); document.write( " How old are they now?
\n" ); document.write( ":
\n" ); document.write( "let f = father's age
\n" ); document.write( "let s = son's age
\n" ); document.write( "let d = daughter's age
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( "\" The father is five times old as the daughter\"
\n" ); document.write( "f = 5d
\n" ); document.write( "\" and the son is 2 years older than the daughter.\"
\n" ); document.write( "s = d + 2
\n" ); document.write( "\" In 10 years, the sum of their three ages will be 81. \"
\n" ); document.write( "(f+10) + s+10) + (d+10) = 81
\n" ); document.write( "f + s + d + 30 = 81
\n" ); document.write( "f + s + d = 81 - 30
\n" ); document.write( "f + s + d = 51
\n" ); document.write( "Replace f with 5d, replace s with (d+2)
\n" ); document.write( "5d + (d+2) + d = 51
\n" ); document.write( "7d = 51 - 2
\n" ); document.write( "d = 49/7
\n" ); document.write( "d = 7 yrs is the daughter's age
\n" ); document.write( "'
\n" ); document.write( "I'll let you find the ages of Dad and son, check by finding their sum in 10 yrs.
\n" ); document.write( ":
\n" ); document.write( "\" \n" ); document.write( "
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