document.write( "Question 859037: If four cards are drawn in succession and without replacement from a standard deck of fifty two cards how many sets of four cards are possible \n" ); document.write( "

Algebra.Com's Answer #517502 by ben720(159) $\"\"$ $\"About$

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\n" ); document.write( "For the first card, there are 52 possibilities to draw.
\n" ); document.write( "For the second card, there are only 51, as you took one away
\n" ); document.write( "For the third card, there are 50
\n" ); document.write( "For the last, there are 49 to choose from.
\n" ); document.write( "For the total number of permutations, there are $\"52%2A51%2A50%2A49\"$ , as for each second card, there are that many first cards to go with it, etc.
\n" ); document.write( "
\n" ); document.write( "So, $\"P=52%2A51%2A50%2A49\"$
\n" ); document.write( "From here, all you have to do is multiply those numbers.
\n" ); document.write( " $\"P=6497400\"$
\n" ); document.write( "
\n" ); document.write( "There are 6497400 possibilities.
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