document.write( "Question 72383: I submitted this problem quite a few days ago and did not get a response. I am resubmitting in hopes to get some help.
\n" ); document.write( "Solve the following word problem. Be sure to show the equation you use for the solution.
\n" ); document.write( "Science and medicine. A bus leaves a station at 1 P.M., traveling west at an average rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart?
\n" ); document.write( "This is what I have so far.
\n" ); document.write( "1st bus leaves=1pm travels west at 44 mi/h
\n" ); document.write( "2nd bus leaves=2pm travels east at 48 mi/h
\n" ); document.write( "274 miles apart
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #51749 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
The first bus travels from 1 p.m. to 2 p.m. at 44 mph. You can compute the distance that
\n" ); document.write( "this bus covers in that hour using the equation:
\n" ); document.write( ".
\n" ); document.write( "D = r*t
\n" ); document.write( ".
\n" ); document.write( "where D stands for distance, r is the rate or speed, and t is the amount of time. For this
\n" ); document.write( "bus the rate is 44 and the elapsed time is 1 hour. So the distance is:
\n" ); document.write( ".
\n" ); document.write( "D - 44*1 = 44 miles.
\n" ); document.write( ".
\n" ); document.write( "So the two buses are already 44 miles apart when the second bus departs at 2 p.m.
\n" ); document.write( ".
\n" ); document.write( "Since the buses are already 44 miles apart at 2 p.m. they only need to separate by 230 more
\n" ); document.write( "miles (274 miles - 44 miles = 230 miles).
\n" ); document.write( ".
\n" ); document.write( "Therefore, starting at 2 p.m. the distances that the two buses travel must add up to be
\n" ); document.write( "230 miles. You can use the distance equation for each bus, noting that their rates
\n" ); document.write( "are different. One bus has a rate of 44 mph and the other 48 mph. So their distances
\n" ); document.write( "are each given by D=r*t and they must add up to be 230 miles. For the first bus you have:
\n" ); document.write( ".
\n" ); document.write( "D = r*t = 44*t
\n" ); document.write( ".
\n" ); document.write( "and for the second bus you have:
\n" ); document.write( ".
\n" ); document.write( "D = r*t = 48*t
\n" ); document.write( ".
\n" ); document.write( "Add these two together and you get:
\n" ); document.write( ".
\n" ); document.write( "44t + 48t = 92t
\n" ); document.write( ".
\n" ); document.write( "(Notice that t is the same for each bus because it is time that started at 2 p.m. and
\n" ); document.write( "both buses are underway after that time. So the elapsed time after 2 p.m. is the same
\n" ); document.write( "for both buses.
\n" ); document.write( ".
\n" ); document.write( "To find the time it takes to cover the 230 miles of additional separation you set the
\n" ); document.write( "92t equal to 230 miles.
\n" ); document.write( ".
\n" ); document.write( "92t = 230
\n" ); document.write( ".
\n" ); document.write( "Divide both sides by 92 to solve for t and you get:
\n" ); document.write( ".
\n" ); document.write( "t = 230/92 = 2.5 hours or 2 hours and 30 minutes after 2 p.m.
\n" ); document.write( ".
\n" ); document.write( "and 2 hours and 30 minutes after 2 p.m. is 4:30 p.m. At that time they are separated
\n" ); document.write( "by the 230 miles plus the 44 mile head start the first bus had, so the total separation is
\n" ); document.write( "230 + 44 = 274 miles.
\n" ); document.write( ".
\n" ); document.write( "Hope this helps you to work your way through the problem. \n" ); document.write( "
\n" );