document.write( "Question 858993: A garden measuring 12 meters by 16 meters is to have a pedestrain pathway installed all around it, increasing the total area to 285 meters. What will be the width of the pathway?
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Algebra.Com's Answer #517465 by mananth(16946)\"\" \"About 
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Let the width of sidewalk be x
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\n" ); document.write( "Length of garden 16 m
\n" ); document.write( "width of garden 12 m
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\n" ); document.write( "Area = 192m^2
\n" ); document.write( "Area of sidewalk = 285-192= 93m^2
\n" ); document.write( "Area of sidewalk 93 m^2
\n" ); document.write( "length of garden & sidewalk 16 + 2 x
\n" ); document.write( "width of garden & sidewalk 12 + 2 x
\n" ); document.write( "Total area - area of garden = 93
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\n" ); document.write( "( 16 + 2 x ) ( 12 + 2 x ) -192 = 93
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\n" ); document.write( " 192 + 32 x + 24 x + 4 X^2 -192 = 93
\n" ); document.write( "4 X^2 + 56 x -93 = 0
\n" ); document.write( "4x^2+56x = 93\r
\n" ); document.write( "\n" ); document.write( "/4
\n" ); document.write( "x^2+14x=93/4\r
\n" ); document.write( "\n" ); document.write( "completing the square method\r
\n" ); document.write( "\n" ); document.write( "x^2+14x+49=93/4 +49\r
\n" ); document.write( "\n" ); document.write( "(x+7)^2 = (196+93)/4\r
\n" ); document.write( "\n" ); document.write( "(x+7)^2= 289/4\r
\n" ); document.write( "\n" ); document.write( "take square root\r
\n" ); document.write( "\n" ); document.write( "(x+7) = +/- sqrt((289)/4)\r
\n" ); document.write( "\n" ); document.write( "(x+7) =+/- 17/2\r
\n" ); document.write( "\n" ); document.write( "x=17/2-7 Taking the positive value\r
\n" ); document.write( "\n" ); document.write( "x= 8.5-7
\n" ); document.write( "x=1.5 m the width of walkway\r
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