document.write( "Question 858788: Starting at home, Christopher traveled uphill to the hardware store for 24 minutes at just 15 mph. He then traveled back home along the same path downhill at a speed of 30 mph.\r
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document.write( "What is his average speed for the entire trip from home to the hardware store and back? \n" );
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Algebra.Com's Answer #517453 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Starting at home, Christopher traveled uphill to the hardware store for 24 minutes at just 15 mph. \n" ); document.write( " He then traveled back home along the same path downhill at a speed of 30 mph. \n" ); document.write( "What is his average speed for the entire trip from home to the hardware store and back? \n" ); document.write( ": \n" ); document.write( "Let d = the one-way distance to the store \n" ); document.write( ": \n" ); document.write( "let a = his average speed for the round trip \n" ); document.write( ": \n" ); document.write( "Write a time equation, time = dist/speed \n" ); document.write( "time up + time back = total time \n" ); document.write( " \n" ); document.write( "multiply by 30a to clear the denominators, results: \n" ); document.write( "2ad + ad = 30(2d) \n" ); document.write( "3ad = 60d \n" ); document.write( "divide both sides by d \n" ); document.write( "3a = 60 \n" ); document.write( "a = 60/3 \n" ); document.write( "a = 20 mph is his average speed for the round trip \n" ); document.write( " |