document.write( "Question 858958: It takes 12 hours to drive a truck to its delivery point and back. The rate going 50 mph, the rate returning is 70 mph. Find the one way distance \n" ); document.write( "
Algebra.Com's Answer #517452 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Let t = time going.
\n" ); document.write( "12-t = time returning, since the total of these times is 12.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Distance going is the same as distance returning.
\n" ); document.write( "RT=D for typical uniform rates travel.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"50t=70%2812-t%29\"
\n" ); document.write( "\"50t=840-70t\"
\n" ); document.write( "\"120t=840\"
\n" ); document.write( "\"highlight_green%28t=7%29\";\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now, what can be done with the value for t?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "... See?
\n" ); document.write( "
\n" );