document.write( "Question 858782: x^2-5x-14 <0 \n" ); document.write( "

Algebra.Com's Answer #517396 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"x%5E2-5x-14+%3C0\"$
\n" ); document.write( " $\"%28x%2B2%29%28x-7%29+%3C0\"$
\n" ); document.write( "When $\"x%3C-2\"$ , left hand side is negative*negative=positive, so not less than zero
\n" ); document.write( "When $\"x%3E7\"$ , left hand side is positive*positive=positive, so not less than zero
\n" ); document.write( "When $\"-2%3Cx%3C7\"$ , left hand side is positive*negative, so less than zero.
\n" ); document.write( "So $\"x%5E2-5x-14%3C0\"$ when $\"-2%3Cx%3C7\"$
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\n" ); document.write( "Verified by the graph
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\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( " $\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E2-5x-14%29\"$
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