document.write( "Question 858086: One line passes through the points (−12,16) and (−1,38). A second line has the equation 2y+x=23. Are these lines parallel, perpendicular, or neither? \n" ); document.write( "

Algebra.Com's Answer #517352 by LinnW(1048) $\"\"$ $\"About$

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Find the slope of the line through (-12,16) (-1,38)
\n" ); document.write( "Set x1 = -12 , y1 = 16 , x2 = -1 , y2 = 38
\n" ); document.write( "in the equation slope = $\"%28y2+-+y1%29%2F%28x2-x1%29\"$
\n" ); document.write( " $\"%2838+-+16%29%2F%28+-1+-+%28-12%29%29\"$ =
\n" ); document.write( "22/11 = 2
\n" ); document.write( "So the slope is 2
\n" ); document.write( "Now find the slope for 2y+x=23
\n" ); document.write( "add -x to each side
\n" ); document.write( "2y = -x + 23
\n" ); document.write( "divide each side by 2
\n" ); document.write( " y = (-1/2)x + 23/2
\n" ); document.write( "So the slope is -1/2
\n" ); document.write( "Since this slope is the negative inverse of 2 we
\n" ); document.write( "have perpendicular lines. $\"%282%29%2A%28-1%2F2%29\"$ = -1 \n" ); document.write( "

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