document.write( "Question 858699: Flying against the wind, a jet travels 5000 mi in 5 hours. Flying with the wind, the same jet travels 12,420mi in 9 hours. What is the rate of the jet in still air and what is the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #517336 by Reham98(4)![]() ![]() ![]() You can put this solution on YOUR website! The rate against the wind is : 5,000/5 = 1,000 miph \n" ); document.write( "The rate with the wind is : 12,420/9 = 1,380 miph\r \n" ); document.write( "\n" ); document.write( "The rate of the wind : 1,380 - 1,000 = 380 miph \n" ); document.write( "The rate of the jet in still aif : 1,000 miph\r \n" ); document.write( "\n" ); document.write( "Though I'm not sure dude x_x \n" ); document.write( " |