document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=858645>Question 858645</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three consecutive terms of an A.P. is 18 and their product is 162.Find the terms. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #517317 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=517317\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of three consecutive terms of an A.P. is 18 and their product is 162.Find the terms.\r<BR>\n" );
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document.write( "let the three terms be <BR>\n" );
document.write( "a-d, a , a+d\r<BR>\n" );
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document.write( "a-d+a+a+d =18\r<BR>\n" );
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document.write( "3a=18<BR>\n" );
document.write( "a=6\r<BR>\n" );
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document.write( "(a-d)(a+d)(a) = 162\r<BR>\n" );
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document.write( "plug a =6\r<BR>\n" );
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document.write( "(6-d)(6+d)(6)=162\r<BR>\n" );
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document.write( "(36-d^2)*6 =162\r<BR>\n" );
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document.write( "36-d^2= 162/6\r<BR>\n" );
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document.write( "36-d^2= 27\r<BR>\n" );
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document.write( "d^2=9\r<BR>\n" );
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document.write( "d= +/-3\r<BR>\n" );
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document.write( "when d=3\r<BR>\n" );
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document.write( "3,6,9<BR>\n" );
document.write( "when d=-3\r<BR>\n" );
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document.write( "9,6,3\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );