document.write( "Question 858633: I am a 2 digit prime number
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document.write( "The sum of my digits is divisible by 4
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document.write( "The product of my digits is less then 5
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document.write( "I am greater then 20
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document.write( "What number am I?
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document.write( "What if I am less then 20? \r
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document.write( "I've been stuck on this question for ages, please help!!
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document.write( "Can you talk me through the steps you take to get the answer? \n" );
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Algebra.Com's Answer #517305 by Edwin McCravy(20059)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "It's good to be able to recognize all the\r\n" ); document.write( "prime numbers less than 100:\r\n" ); document.write( "\r\n" ); document.write( "2, 3, 5, 7, 11, 13, 17, 19, 23, 29, \r\n" ); document.write( "31, 37, 41, 43, 47, 53, 59, 61, 67,\r\n" ); document.write( "71, 73, 79, 83, 89, 97.\r\n" ); document.write( "\r\n" ); document.write( "Those greater than 20 are\r\n" ); document.write( "\r\n" ); document.write( "23, 29, 31, 37, 41, 43, 47, 53, 59,\r\n" ); document.write( "61, 67, 71, 73, 79, 83, 89, 97.\r\n" ); document.write( "\r\n" ); document.write( "The only one that has sum of digits 4 is 31, since 3+1=4.\r\n" ); document.write( "\r\n" ); document.write( "31 is greater than 20.\r\n" ); document.write( "\r\n" ); document.write( "The product of its digits is 3×1 = 3, which is less than 5\r\n" ); document.write( "\r\n" ); document.write( "----------------------------------------------------------\r\n" ); document.write( "\r\n" ); document.write( "All the two-digit prime numbers less than 20 are\r\n" ); document.write( "\r\n" ); document.write( "11, 13, 17, 19\r\n" ); document.write( "\r\n" ); document.write( "The only one with sum of digits 4 is 13, since 1+3=4. \r\n" ); document.write( "\r\n" ); document.write( "Its product of digits is 1×3 = 3, which is less than 5.\r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |