document.write( "Question 858601: A man invests his savings in two accounts, one paying 6 percent and the other paying 10 percent simple interest per year. He puts twice as much in the lower-yielding account because it is less risky. His annual interest is 10956 dollars. How much did he invest at each rate? How much interest was earned on each account? \n" ); document.write( "
Algebra.Com's Answer #517298 by mananth(16946)\"\" \"About 
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10%--------------x\r
\n" ); document.write( "\n" ); document.write( "6%--------------2x\r
\n" ); document.write( "\n" ); document.write( "10%x+6% * 2x=10956\r
\n" ); document.write( "\n" ); document.write( "multiply by 100\r
\n" ); document.write( "\n" ); document.write( "10x+12x=1095600\r
\n" ); document.write( "\n" ); document.write( "22x= 1095600\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x=1095600/22\r
\n" ); document.write( "\n" ); document.write( "x= 49,800--------------10%------------------$4980\r
\n" ); document.write( "\n" ); document.write( "2x= 99,600--------------6%-------------------$ 5976
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