document.write( "Question 858600: Phyllis invested 64000 dollars, a portion earning a simple interest rate of 4 percent per year and the rest earning a rate of 7 percent per year. After one year the total interest earned on these investments was 3730 dollars. How much money did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #517297 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 4.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 7.00% per annum ------------ Amount invested = y \n" ); document.write( " 67000 \n" ); document.write( "Interest----- 3730.00 \n" ); document.write( " \n" ); document.write( "Part I 4.00% per annum ---x \n" ); document.write( "Part II 7.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 67000 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "4.00% x + 7.00% y= 3730 \n" ); document.write( "Multiply by 100 \n" ); document.write( "4 x + 7 y= 373000.00 --------2 \n" ); document.write( "Multiply (1) by -4 \n" ); document.write( "we get \n" ); document.write( "-4 x -4 y= -268000.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x 3 y= 105000 \n" ); document.write( "divide by 3 \n" ); document.write( " y = 35000 \n" ); document.write( "Part I 4.00% $ 32000 \n" ); document.write( "Part II 7.00% $ 35000 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "32000 --------- 4.00% ------- 1280.00 \n" ); document.write( "35000 ------------- 7.00% ------- 2450.00 \n" ); document.write( "Total -------------------- 3730.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |