document.write( "Question 858609: calculus. A cylindrical container is to hold 20π cm3. The bottom is made of a material that costs $0.80 per cm2, and the top is left open (no material needed). The material for the curved side costs $0.32 per cm2.
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Algebra.Com's Answer #517291 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Let h = height, r = radius.
\n" ); document.write( "Let A = surface area
\n" ); document.write( "Let v=volume\r
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\n" ); document.write( "\n" ); document.write( "\"A=2%2Api%2Ar%5E2%2Ah%2Bpi%2Ar%5E2\".\r
\n" ); document.write( "\n" ); document.write( "\"v=h%2Api%2Ar%5E2=20pi\".
\n" ); document.write( "Solve this for h:
\n" ); document.write( "\"h=20%2F%28r%5E2%29\", and substituting into the A equation,
\n" ); document.write( "\"A=2%2Api%2Ar%2820%2F%28r%5E2%29%29%2Bpi%2Ar%5E2\"
\n" ); document.write( "\"A=40%2Api%2Fr%2Bpi%2Ar%5E2\",which you will use for applying the costs of the two different parts.\r
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\n" ); document.write( "\n" ); document.write( "Now, applying the cost to those two area parts, cost as a function of r, C(r) becomes:
\n" ); document.write( "\"C%28r%29=%280.32%2940%2Api%2Fr%2B%280.80%29pi%2Ar%5E2\"
\n" ); document.write( "\"highlight_green%28C%28r%29=12.8%2Api%2Fr%2B%280.80%29pi%2Ar%5E2%29\".
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\n" ); document.write( "You want to minimize the cost. Find the derivative of C with regard to r, set equal to zero, and solve this for r. You then use this to find your value of h.\r
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\n" ); document.write( "\n" ); document.write( "You might also want to check your result using a graphing calculator for the cost equation without use of Calculus.
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