document.write( "Question 858305: A train 600 metre long passes a car running at 72 km/hr in same direction in which the train going in 10 seconds. Calculate the speed of the train.
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document.write( "A. 108km/hr
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document.write( "B.252 km/hr
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document.write( "C.162km/hr
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document.write( "D.225 km/hr \n" );
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Algebra.Com's Answer #517278 by KMST(5328)![]() ![]() You can put this solution on YOUR website! According to my calculations the answer is \"none of the above.\" \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ONE WAY TO CALCULATE IT: \n" ); document.write( "From the point of view of a passenger in the car, \n" ); document.write( "the car is not moving, and the train is going past the car at \n" ); document.write( " \n" ); document.write( "One moment the passenger sees the front of the train level with the car, \n" ); document.write( "and 10 seconds later the passenger seens the back of the train level with the car. Since at that point, the front of the train is \n" ); document.write( " \n" ); document.write( "So \n" ); document.write( "So the speed of the train with respect to the ground is 80 m/s. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANOTHER WAY TO SEE IT: \n" ); document.write( "One moment, the train is level with the car, at a certain spot on the road. \n" ); document.write( "After \n" ); document.write( "At the same time, going at a faster rate, the front of the train is many meters ahead of that initial spot. \n" ); document.write( "The back of the train is now level with the car. \n" ); document.write( "Since the front of the train is \n" ); document.write( "the front of the train is 200m + 600 m = 800m ahead of that initial spot where car and train first met. \n" ); document.write( "The train has covered 800m in 10 seconds, so the speed of the train with respect to the ground is 80 m/s. \n" ); document.write( " |