document.write( "Question 858305: A train 600 metre long passes a car running at 72 km/hr in same direction in which the train going in 10 seconds. Calculate the speed of the train.
\n" ); document.write( "A. 108km/hr
\n" ); document.write( "B.252 km/hr
\n" ); document.write( "C.162km/hr
\n" ); document.write( "D.225 km/hr
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Algebra.Com's Answer #517278 by KMST(5328)\"\" \"About 
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According to my calculations the answer is \"none of the above.\"
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\n" ); document.write( "\"x\"= speed of the train with respect to the ground, in m/s.
\n" ); document.write( "\"%22%2F+second%22\" is the car's speed.
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\n" ); document.write( "ONE WAY TO CALCULATE IT:
\n" ); document.write( "From the point of view of a passenger in the car,
\n" ); document.write( "the car is not moving, and the train is going past the car at
\n" ); document.write( "\"x-20\" m/s.
\n" ); document.write( "One moment the passenger sees the front of the train level with the car,
\n" ); document.write( "and 10 seconds later the passenger seens the back of the train level with the car. Since at that point, the front of the train is \"600+m\" ahead of the car, the apparent speed of the train (from the car passenger's point of view is
\n" ); document.write( "\"600m%2F%2210+seconds%22=60\"m/s.
\n" ); document.write( "So \"x-20=60\"-->\"x=60%2B20\"-->\"x=80\"
\n" ); document.write( "So the speed of the train with respect to the ground is 80 m/s.
\n" ); document.write( "\"%22km+%2F+hr%22\"
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\n" ); document.write( "ANOTHER WAY TO SEE IT:
\n" ); document.write( "One moment, the train is level with the car, at a certain spot on the road.
\n" ); document.write( "After \"10\" seconds, at 20m/s, the car is 200 m ahead of that initial spot.
\n" ); document.write( "At the same time, going at a faster rate, the front of the train is many meters ahead of that initial spot.
\n" ); document.write( "The back of the train is now level with the car.
\n" ); document.write( "Since the front of the train is \"600\" meters ahead of that,
\n" ); document.write( "the front of the train is 200m + 600 m = 800m ahead of that initial spot where car and train first met.
\n" ); document.write( "The train has covered 800m in 10 seconds, so the speed of the train with respect to the ground is 80 m/s.
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