document.write( "Question 858557: One number is is 3 less than a second number. Twice the second number is 34 more than 4 times the first. Find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #517276 by JulietG(1812)\"\" \"About 
You can put this solution on YOUR website!
Let A be the first number, and B the second.
\n" ); document.write( "A = B-3 [One number is is 3 less than a second number]
\n" ); document.write( "2B = 4A + 34 [Twice the second number is 34 more than 4 times the first.]
\n" ); document.write( "Substitute the known value of A from the first equation into the second.
\n" ); document.write( "2B = 4(B-3) + 34
\n" ); document.write( "Distribute
\n" ); document.write( "2B = 4B-12+34
\n" ); document.write( "Add
\n" ); document.write( "2B = 4B + 22
\n" ); document.write( "Subtract 22 from each side
\n" ); document.write( "2B - 22 = 4B
\n" ); document.write( "Subtract 2B from each side
\n" ); document.write( "-22 = 2B
\n" ); document.write( "Divide each side by 2
\n" ); document.write( "-11 = B
\n" ); document.write( ".
\n" ); document.write( "If B = -11, then A is -14.
\n" ); document.write( "Let's make sure this works.
\n" ); document.write( "twice -11 should be 34 more than 4x -14
\n" ); document.write( "-22 = 34 - 56
\n" ); document.write( "Success!
\n" ); document.write( " \n" ); document.write( "
\n" );