document.write( "Question 858599: Margo borrows $100, agreeing to pay it back with 6% annual interest after 13 months. How much interest will she pay?\r
\n" ); document.write( "\n" ); document.write( "Round your answer to the nearest cent, if necessary.
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Algebra.Com's Answer #517272 by JulietG(1812)\"\" \"About 
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100 * .06 = $6 interest per year
\n" ); document.write( "If it's compounded ANNUALLY, she'll owe $106 at the end of 12 months.
\n" ); document.write( "Since she is contracting to pay it back in 13 months, it will be compounded again at the end of the 13th month.
\n" ); document.write( "$106 * .005 (1/12th of the 6% interest) = .53
\n" ); document.write( "Total to pay back: 106.53
\n" ); document.write( "Amount of interest: 6.53
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\n" ); document.write( "If, however, she is paying it back with interest calculated at the end of the 13 months instead of annually, she'll pay:
\n" ); document.write( "100 * 6.5 (6% interest + \"1%2F2\"% interest)
\n" ); document.write( "Total to pay back: 106.50
\n" ); document.write( "Amount of interest: 6.50
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