document.write( "Question 858432: A corner lot that originally was square lost 185 meters squared of area when one of the adjacent streets was widened by 3 meters and the other was widened by 5 meters. Find the new dimensions of the lot. \n" ); document.write( "
Algebra.Com's Answer #517224 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A corner lot, that originally was square, lost 185 meters squared of area when one of the adjacent streets was widened by 3 meter and the other was widened by 5 meters.
\n" ); document.write( " Find the new dimensions of the lot.
\n" ); document.write( ":
\n" ); document.write( "Let x = original length of the square lot
\n" ); document.write( "the
\n" ); document.write( "x^2 = original area of the lot
\n" ); document.write( ":
\n" ); document.write( "(x-3) = new length
\n" ); document.write( "and
\n" ); document.write( "(x-5) = new width
\n" ); document.write( ":
\n" ); document.write( "Original area - new area = 185 sq/m
\n" ); document.write( "x^2 - (x-5)(x-3) = 185
\n" ); document.write( "FOIL
\n" ); document.write( "x^2 - (x^2 - 8x + 15) = 185
\n" ); document.write( "x^2 - x^2 + 8x - 15 = 185
\n" ); document.write( "8x = 185 + 15
\n" ); document.write( "x = 200/8
\n" ); document.write( "x = 25 meter is the original side of the lost
\n" ); document.write( "then
\n" ); document.write( "25 - 3 = 22 meters is then new length
\n" ); document.write( "25 - 5 = 20 meters is the new width
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the areas
\n" ); document.write( "25*25 = 625 sq/m
\n" ); document.write( "22*20 = 440
\n" ); document.write( "-------------
\n" ); document.write( "dif: 185 sq/m \n" ); document.write( "
\n" );