document.write( "Question 858246: Chris needs to mix a 20% alcohol solution with a 60% alcohol solution to create 200 millileters of a 54% solution. How many millileters of each solution must Chris use?
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Algebra.Com's Answer #517126 by ramkikk66(644) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Let the volume of 20% sol be x\r\n" );
document.write( "Then volume of 60% sol is 200 - x\r\n" );
document.write( "Alcohol in 20% sol = \r\n" );
document.write( "Alcohol in 60% sol = \r\n" );
document.write( "If the final solution is of 54% concentration, it means the volume of alcohol in it\r\n" );
document.write( "=  \r\n" );
document.write( "So we have the equation\r\n" );
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document.write( "So he takes 30 ml of 20% alcohol and 170 ml of 60% alcohol\r\n" );
document.write( "Check:\r\n" );
document.write( "30 ml contains 30 * 20% = 6 ml of alcohol\r\n" );
document.write( "170 ml contains 170 * 60% = 102 ml of alcohol\r\n" );
document.write( "Total alcohol = 6 + 102 = 108 which is 54% of 200 ml. Correct!\r\n" );
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