document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=858158>Question 858158</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Among all rectangles that have a perimeter of 102, find the dimensions of the one whose area is largest.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #517119 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=517119\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the perimeter = 102, then L + W = 51 (perimeter is 2L + 2W)<BR>\n" );
document.write( "The numbers closest together are going to yield the highest area.<BR>\n" );
document.write( "Any numbers that equal 51 are going to work.  What two numbers are closest to each other? 51/2 = 25.5<BR>\n" );
document.write( "Length = 26, Width = 25, Area = 25 * 26 = 650<BR>\n" );
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document.write( "You can test that.  Pick any other two.  How about 50 and 1?<BR>\n" );
document.write( "50 * 1 = 50<BR>\n" );
document.write( "Maybe 30 and 21.  30*21=630<BR>\n" );
document.write( "20*31=620<BR>\n" );
document.write( "5*46 =230<BR>\n" );
document.write( "etc, etc, etc.  It's always going to be the two numbers closest together that yield the highest area. </SPAN>\n" );
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