document.write( "Question 858163: Solve the equation. Check for any extraneous solutions.\r
\n" ); document.write( "\n" ); document.write( "(sqrt(2-x)) = x+4 \n" ); document.write( "

Algebra.Com's Answer #517118 by mananth(16946) $\"\"$ $\"About$

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$\"%28sqrt%282-x%29%29+=+x%2B4\"$ \r
\n" ); document.write( "\n" ); document.write( "square both sides of the equation\r
\n" ); document.write( "\n" ); document.write( "(2-x) = (x+4)^2\r
\n" ); document.write( "\n" ); document.write( "2-x= x^2+8x+16\r
\n" ); document.write( "\n" ); document.write( "x^2+9x-14=0\r
\n" ); document.write( "\n" ); document.write( "x^2+9x =14\r
\n" ); document.write( "\n" ); document.write( "x^2+9x+(9/2)^2 =14 +(9/2)^2\r
\n" ); document.write( "\n" ); document.write( "(x+9/2)^2 = 14+(81/4)\r
\n" ); document.write( "\n" ); document.write( "(x+9/2)^2 = (56+81)/4\r
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\n" ); document.write( "\n" ); document.write( "(x+9/2)^2 = (137)/4\r
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\n" ); document.write( "\n" ); document.write( "take square root\r
\n" ); document.write( "\n" ); document.write( "x+9/2 = +/-sqrt(137)/2\r
\n" ); document.write( "\n" ); document.write( "x= -9/2 +/- sqrt(137)/2\r
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