document.write( "Question 858224: From the top of a vertical cliff 68 metres high, an observer notices a yacht at sea.
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document.write( "The angle of depression to the yacht is 47 degrees. The yacht sails directly away from the cliff,
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document.write( "and after 10 minutes the angle of depression is 15 degrees. How fast does the yacht sail? \n" );
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Algebra.Com's Answer #517113 by mananth(16946)![]() ![]() You can put this solution on YOUR website! height of tower = 68m\r \n" ); document.write( "\n" ); document.write( "angle of depression = 47 deg\r \n" ); document.write( "\n" ); document.write( "angle of depression after 10 minutes = 15 deg\r \n" ); document.write( "\n" ); document.write( "10 min = 600 seconds\r \n" ); document.write( "\n" ); document.write( "Let the initial ground distance from tower to yacht x m\r \n" ); document.write( "\n" ); document.write( "Tan 47 = 68/x \n" ); document.write( "x= 68/tan 47\r \n" ); document.write( "\n" ); document.write( "Let the speed of the yacht = y\r \n" ); document.write( "\n" ); document.write( "distance traveled in 600 seconds = 600y\r \n" ); document.write( "\n" ); document.write( "Tan 15 = 68/(x+600y) \r \n" ); document.write( "\n" ); document.write( "x+600y = 68/tan 15\r \n" ); document.write( "\n" ); document.write( "x= (68/tan 15)-600y\r \n" ); document.write( "\n" ); document.write( "68/tan47 = (68/tan 15)-600y\r \n" ); document.write( "\n" ); document.write( "600y = (68/tan 15)- (68/tan 47)\r \n" ); document.write( "\n" ); document.write( "600y=253.8-63.4\r \n" ); document.write( "\n" ); document.write( "y=0.32 m/s------ speed of the yacht \n" ); document.write( " |