document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=72310>Question 72310</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the folling 2 x 2 systems using substitutions\r<BR>\n" );
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document.write( "y= 3x + 12<BR>\n" );
document.write( "y= -x +4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51711 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51711\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y= 3x + 12<BR>\n" );
document.write( "y= -x +4\r<BR>\n" );
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document.write( "plug -x + 4 into the first equation for the y;<BR>\n" );
document.write( "-x + 4 = 3x +12<BR>\n" );
document.write( "-x -3x +4 = 12<BR>\n" );
document.write( "-4x = 12 - 4<BR>\n" );
document.write( "-4x = 8<BR>\n" );
document.write( "x = -2<BR>\n" );
document.write( "now plug that in the equation for x;<BR>\n" );
document.write( "y = 3(-2) + 12<BR>\n" );
document.write( "y = -6+12<BR>\n" );
document.write( "y = 6<BR>\n" );
document.write( ":) </SPAN>\n" );
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