document.write( "Question 858145: what is the solution to the following question: log base 4 of sqrt 2x-5=x+1 \n" ); document.write( "
Algebra.Com's Answer #517094 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"log%284%2Csqrt%282x-5%29%29=x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%284%2C%282x-5%29%5E%280.5%29%29=x%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"%280.5%29log%284%2C2x-5%29=x%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"log%284%2C2x-5%29=%28x%2B1%29%2F0.5=%28x%2B1%29%2F%281%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%284%2C2x-4%29=2x%2B2\"\r
\n" ); document.write( "\n" ); document.write( "The best next step is to restate the equation in exponential form and continue to solve for x. I stop here and let you finish.
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