document.write( "Question 858189: A rectangle has a perimeter of 34 cm and an area of 52 cm2. Its length is 5 more than twice its width. What are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #517091 by lwsshak3(11628)\"\" \"About 
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A rectangle has a perimeter of 34 cm and an area of 52 cm2. Its length is 5 more than twice its width. What are the dimensions of the rectangle?
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\n" ); document.write( "let x=width
\n" ); document.write( "2x+5=length\r
\n" ); document.write( "\n" ); document.write( "2(length+width)=perimeter
\n" ); document.write( "2(x+2x+5)=34
\n" ); document.write( "6x+10=34
\n" ); document.write( "6x=24
\n" ); document.write( "x=4
\n" ); document.write( "width=4
\n" ); document.write( "length=2x+5=13
\n" ); document.write( "...
\n" ); document.write( "length * width=area
\n" ); document.write( "x(2x+5)=52
\n" ); document.write( "2x^2+5x=52
\n" ); document.write( "2x^2+5x-52=0
\n" ); document.write( "(x-4)(2x+13)=0
\n" ); document.write( "x=4
\n" ); document.write( "width=4
\n" ); document.write( "length=13
\n" ); document.write( "
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