document.write( "Question 856885: Ten cards are numbered 1 to 10. Three different cards are selected at random from these cards. What is the probability that the sum of the numbers obtained is at most 9? \n" ); document.write( "
Algebra.Com's Answer #517071 by Edwin McCravy(20055)\"\" \"About 
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document.write( "The smallest sum the three can have is 6; 1+2+3 = 6.\r\n" );
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document.write( "There is only 1 way the sum can be 6, that is 1+2+3=6\r\n" );
document.write( "There is only 1 way the sum can be 7, that is 1+2+4=7\r\n" );
document.write( "There are 2 ways the sum can be 8, they are 1+2+5=8 and 1+3+4=8\r\n" );
document.write( "There are 3 ways the sum can be 9, they are 1+2+6=9, 1+3+5=9, and 2+3+4=9\r\n" );
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document.write( "That's 7 successful ways of getting a sum of 9 or less.\r\n" );
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document.write( "The total number of ways  of getting any sum is C(10,3) = 120 ways.\r\n" );
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document.write( "Probability of a successful sum = \"7%2F120\", \r\n" );
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document.write( "(which, incidentally is less than 6% of the time.) \r\n" );
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document.write( "Edwin
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