document.write( "Question 858161: I'm not sure how to figure this problem out \r
\n" ); document.write( "\n" ); document.write( "If the perimeter of a rectangle is 74 ft and the length of the rectangle is 5 less than twice it's width: I also have to find the dimension, area of the rectangle, How would I do that? \n" ); document.write( "
Algebra.Com's Answer #517064 by JulietG(1812)\"\" \"About 
You can put this solution on YOUR website!
We know that a perimeter is a fence around. It requires 2 pieces of width and 2 pieces of length.
\n" ); document.write( "2W + 2L = 74 [the perimeter of a rectangle is 74 ft ]
\n" ); document.write( "L = 2W - 5 [the length of the rectangle is 5 less than twice its width]
\n" ); document.write( "Substitute the value of L in the second equation for the value of L in the first.
\n" ); document.write( "2W + 2(2W-5) = 74
\n" ); document.write( "Distribute
\n" ); document.write( "2W + 4W - 10 = 74
\n" ); document.write( "Add the Ws
\n" ); document.write( "6W - 10 = 74
\n" ); document.write( "Add 10 to each side
\n" ); document.write( "6W = 84
\n" ); document.write( "Divide each side by 6
\n" ); document.write( "W = 14
\n" ); document.write( "If the width is 14 and the length is twice that minus 5, then length is 14+14-5, or 23.
\n" ); document.write( ".
\n" ); document.write( "To find the area, multiply length times width.
\n" ); document.write( "23 * 14 = 322 sf
\n" ); document.write( " \n" ); document.write( "
\n" );