document.write( "Question 858001: A and B play a game in which B's probability of winning is 2/3 if they play five games what is probability A will win atleast one game \n" ); document.write( "
Algebra.Com's Answer #517059 by ben720(159)\"\" \"About 
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\n" ); document.write( "An easier way to think about it is to look at the probability of
\n" ); document.write( "1-(B winning all the time)
\n" ); document.write( "Or in other words all the times except where B always wins.
\n" ); document.write( "The chance of B winning the first time is \"2%2F3\". The chance of him winning twice in a row is \"4%2F9\", because you need to multiply the 2/3's together to reflect them both happening. If they play 5 games, the probability of him winning all the time would be:
\n" ); document.write( "\"2%2F3%2A2%2F3%2A2%2F3%2A2%2F3%2A2%2F3\"
\n" ); document.write( "When you multiply all the numerators and denominators, you get
\n" ); document.write( "\"2%5E5%2F3%5E5\"
\n" ); document.write( "Calculate those numbers, and you get:
\n" ); document.write( "\"32%2F243\"
\n" ); document.write( "The answer, however is 1-\"32%2F243\", or
\n" ); document.write( "\"243%2F243-32%2F243\"
\n" ); document.write( "\"%28243-32%29%2F243\"
\n" ); document.write( "\"211%2F243\"
\n" ); document.write( "This is your final answer. If you want a percent, it's ≈86.83%
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