document.write( "Question 858136: What are the values that satisfy the trigonometric equation for 0 < q < 2
\n" ); document.write( "sin(θ)+tan(-θ)=0
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Algebra.Com's Answer #517053 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'm going to use x in place of theta\r
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\n" ); document.write( "\n" ); document.write( "sin(x)+tan(-x)=0\r
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\n" ); document.write( "\n" ); document.write( "sin(x)-tan(x)=0 ... since tan(x) is odd\r
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\n" ); document.write( "\n" ); document.write( "sin(x)-sin(x)/cos(x)=0\r
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\n" ); document.write( "\n" ); document.write( "sin(x)*cos(x)/cos(x)-sin(x)/cos(x)=0\r
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\n" ); document.write( "\n" ); document.write( "( sin(x)*cos(x)-sin(x) )/cos(x)=0\r
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\n" ); document.write( "\n" ); document.write( "sin(x)*cos(x)-sin(x) = 0*cos(x)\r
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\n" ); document.write( "\n" ); document.write( "sin(x)*cos(x)-sin(x) = 0\r
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\n" ); document.write( "\n" ); document.write( "sin(x)( cos(x)-1 ) = 0\r
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\n" ); document.write( "\n" ); document.write( "sin(x) = 0 or cos(x)-1 = 0\r
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\n" ); document.write( "\n" ); document.write( "sin(x) = 0 or cos(x) = 1\r
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\n" ); document.write( "\n" ); document.write( "x = arcsin(0) or x = arccos(1)\r
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\n" ); document.write( "\n" ); document.write( "x = 0, pi or x = 0\r
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\n" ); document.write( "\n" ); document.write( "So if x is in the interval [0, 2pi), then the solutions are: x = 0, x = pi
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