document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=858128>Question 858128</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dolores' bank balance is three times Dudley's. Three times Dolores' balance increased by 60 is ten times Dudley's balance. what is each person's balance? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #517043 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=517043\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let D represent Dolores, and Y represent Dudley.<BR>\n" );
document.write( "D = 3Y [Dolores' bank balance is three times Dudley's.]<BR>\n" );
document.write( "3D + 60 = 10Y [Three times Dolores' balance increased by 60 is ten times Dudley's balance.]<BR>\n" );
document.write( "Substitute the known value of D from the first equation into the second.<BR>\n" );
document.write( "3(3Y) + 60 = 10Y<BR>\n" );
document.write( "9Y + 60 = 10Y<BR>\n" );
document.write( "Subtract 9Y from each side<BR>\n" );
document.write( "60 = Y<BR>\n" );
document.write( ".<BR>\n" );
document.write( "If Dudley's balance is 60, then Delores' is 180 (3 times)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let's see if that works in the second equation.<BR>\n" );
document.write( "3*D (3*180=540) + 60 = 10*Y (10*60 = 600)<BR>\n" );
document.write( "540 + 60 = 600<BR>\n" );
document.write( "600=600<BR>\n" );
document.write( "Success! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );