document.write( "Question 857554: What is the area of a rectangle with the length of $\"6a%5E2b\"$ and a width of $\"3ab\"$ ? \n" ); document.write( "

Algebra.Com's Answer #517041 by ben720(159) $\"\"$ $\"About$

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\n" ); document.write( "Area = Length times Width
\n" ); document.write( "Let A=area
\n" ); document.write( " $\"A=%286a%5E2b%29%283ab%29\"$
\n" ); document.write( "Reorder factors
\n" ); document.write( " $\"A=6%2A3%2Aa%5E2%2Aa%2Ab%2Ab\"$
\n" ); document.write( "Extend exponents, multiply 6&3
\n" ); document.write( " $\"A=18%2Aa%2Aa%2Aa%2Ab%2Ab\"$
\n" ); document.write( "Combine like terms. a*a*a = a^3, b*b = b^2, as there are 3 a's and 2 b's
\n" ); document.write( " $\"A=18a%5E3b%5E2\"$
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\n" ); document.write( "The area of the rectangle is $\"18a%5E3b%5E2\"$
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