document.write( "Question 858119: (200x)/((10^2+x^2)^1/2)-160=0\r
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document.write( "need a step by step solution i know the answer i just can't solve it the answer is 40/3 \n" );
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Algebra.Com's Answer #517037 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! (200x)/((10^2+x^2)^1/2)-160=0 \n" ); document.write( "(200x)/((100+x^2)^1/2)=160 \n" ); document.write( "5x/((100+x^2)^1/2)=4\r \n" ); document.write( "\n" ); document.write( "5x=4*((100+x^2)^1/2) \n" ); document.write( "5/4x=((100+x^2)^1/2) \n" ); document.write( "25/16x=100+x^2\r \n" ); document.write( "\n" ); document.write( "9/16x^2=100 \n" ); document.write( "3/4x=10 \n" ); document.write( "x=4/3*10 \n" ); document.write( "x=40/3\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |