document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=857850>Question 857850</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equaiton in standard form of the parabola with the directrix x = 3 and vertex (1,-2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #517013 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=517013\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the equaiton in standard form of the parabola with the directrix x = 3 and vertex (1,-2)<BR>\n" );
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document.write( "Sketch a picture of the directrix and the vertex.<BR>\n" );
document.write( "Since the vertex is to the left of a vertical directrix,<BR>\n" );
document.write( "the parabola form is (y-k)^2 = 4p(x-h) where 4p is negative.<BR>\n" );
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document.write( "p = 1-3 = -2<BR>\n" );
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document.write( "(y-k)^2 = 4p(x-h)<BR>\n" );
document.write( "(y+2)^2 = -8(x-1)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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