document.write( "Question 857342: josie has twice as many nickels as dimes and five less quarters than dimes. if she had a total of $5.95. how much of each coins does she have \n" ); document.write( "
Algebra.Com's Answer #516996 by ben720(159)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "If you Let X=dimes, then \n" ); document.write( "2(X)*0.05 nickels + X*0.1 dimes + (X-5)*0.25 = $5.95 \n" ); document.write( " \n" ); document.write( "Then, add 1.25 to both sides, \n" ); document.write( " \n" ); document.write( "Combine Like Terms \n" ); document.write( " \n" ); document.write( "Divide by 0.45 on both sides \n" ); document.write( " \n" ); document.write( "You have X dimes, 2X nickels, and X-5 quarters. \n" ); document.write( "Substitute to get 16 dimes, 32 nickels, and 11 quarters. \n" ); document.write( " \n" ); document.write( "To check, see if \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Your final, checked answer is 16 dimes, 32 nickels, and 11 quarters. \n" ); document.write( " |