document.write( "Question 857342: josie has twice as many nickels as dimes and five less quarters than dimes. if she had a total of $5.95. how much of each coins does she have \n" ); document.write( "
Algebra.Com's Answer #516996 by ben720(159)\"\" \"About 
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\n" ); document.write( "If you Let X=dimes, then
\n" ); document.write( "2(X)*0.05 nickels + X*0.1 dimes + (X-5)*0.25 = $5.95
\n" ); document.write( "\"X%2A0.1+%2B+X%2A0.1+%2B+X%2A0.25+-+1.25+=+5.95\"
\n" ); document.write( "Then, add 1.25 to both sides,
\n" ); document.write( "\"X%2A0.1+%2B+X%2A0.1+%2B+X%2A0.25+=+7.20\"
\n" ); document.write( "Combine Like Terms
\n" ); document.write( "\"X%2A0.45+=+7.20\"
\n" ); document.write( "Divide by 0.45 on both sides
\n" ); document.write( "\"X+=+16\"
\n" ); document.write( "You have X dimes, 2X nickels, and X-5 quarters.
\n" ); document.write( "Substitute to get 16 dimes, 32 nickels, and 11 quarters.
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\n" ); document.write( "To check, see if \"16%2A0.1+%2B+32%2A0.05+%2B+11%2A0.25+=+5.95\"
\n" ); document.write( "\"1.6%2B1.6%2B2.75=5.95\"
\n" ); document.write( "\"5.95=5.95\" True
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\n" ); document.write( "Your final, checked answer is 16 dimes, 32 nickels, and 11 quarters.
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