document.write( "Question 857368: Find three consecutive integers such that two times the sum of all three is 3 times the product of the larger two. \n" ); document.write( "
Algebra.Com's Answer #516993 by ben720(159)\"\" \"About 
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\n" ); document.write( "For three consecutive integers,
\n" ); document.write( "Let X = 1st
\n" ); document.write( "X+1 = 2nd
\n" ); document.write( "X+2 = 3rd
\n" ); document.write( "Therefore, the sum of the three is X+(X+1)+(X+2), or 3X+3 total.
\n" ); document.write( "For the equation, twice the sum is 3 times the product of the larger two, or
\n" ); document.write( "\"2%283X%2B3%29=3%28X%2B1%29%28X%2B2%29\"
\n" ); document.write( "From here, distribute
\n" ); document.write( "\"6X%2B6=%283X%2B3%29%28X%2B2%29\"
\n" ); document.write( "Then, distribute some more...
\n" ); document.write( "\"6X%2B6=3X%5E2%2B9X%2B6\"
\n" ); document.write( "Subtract (6X+6)
\n" ); document.write( "\"0=3X%5E2%2B3X%2B0\"
\n" ); document.write( "Then, use the quadratic formula to find your two X's
\n" ); document.write( "\"X=%28-3%2B-sqrt%283%5E2-4%2A3%2A0%29%29%2F%282%2A3%29\"
\n" ); document.write( "Do the appropriate multiplication
\n" ); document.write( "\"X=%28-3%2B-sqrt%289-0%29%29%2F%286%29\"
\n" ); document.write( "Keep simplifying
\n" ); document.write( "\"X=%28-3%2B3%29%2F6\"or\"X=%28-3-3%29%2F6\"
\n" ); document.write( "So the answer is either\"X=%28-3%2B3%29%2F6=0\" or \"X=%28-3-3%29%2F6=-6%2F6=-1.\"
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\n" ); document.write( "And so, the two answers for X are 0 and -1. The second is X + 1, third is X + 2.
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\n" ); document.write( "Your 2 answers are 0, 1, 2 or -1, 0, 1.
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\n" ); document.write( "To check, plug each of them in:
\n" ); document.write( "\"2%280%2B1%2B2%29=3%281%2A2%29\"
\n" ); document.write( "\"2%283%29=3%282%29\"
\n" ); document.write( "\"6=6\"
\n" ); document.write( "Next, try -1, 0, 1:
\n" ); document.write( "\"2%28-1%2B0%2B1%29=3%280%2A1%29\"
\n" ); document.write( "\"2%280%29=3%280%29\"
\n" ); document.write( "\"0=0\"
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\n" ); document.write( "Your final, checked answers are 0, 1, and 2; or -1, 0, and 1.
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