document.write( "Question 857368: Find three consecutive integers such that two times the sum of all three is 3 times the product of the larger two. \n" ); document.write( "
Algebra.Com's Answer #516993 by ben720(159)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "For three consecutive integers, \n" ); document.write( "Let X = 1st \n" ); document.write( "X+1 = 2nd \n" ); document.write( "X+2 = 3rd \n" ); document.write( "Therefore, the sum of the three is X+(X+1)+(X+2), or 3X+3 total. \n" ); document.write( "For the equation, twice the sum is 3 times the product of the larger two, or \n" ); document.write( " \n" ); document.write( "From here, distribute \n" ); document.write( " \n" ); document.write( "Then, distribute some more... \n" ); document.write( " \n" ); document.write( "Subtract (6X+6) \n" ); document.write( " \n" ); document.write( "Then, use the quadratic formula to find your two X's \n" ); document.write( " \n" ); document.write( "Do the appropriate multiplication \n" ); document.write( " \n" ); document.write( "Keep simplifying \n" ); document.write( " \n" ); document.write( "So the answer is either \n" ); document.write( " \n" ); document.write( "And so, the two answers for X are 0 and -1. The second is X + 1, third is X + 2. \n" ); document.write( " \n" ); document.write( "Your 2 answers are 0, 1, 2 or -1, 0, 1. \n" ); document.write( " \n" ); document.write( "To check, plug each of them in: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Next, try -1, 0, 1: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Your final, checked answers are 0, 1, and 2; or -1, 0, and 1. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |