document.write( "Question 858018: Find the value of x in degree 5 (sin ^2)x + 12 sin x + 4 = 0 \n" ); document.write( "
Algebra.Com's Answer #516974 by stanbon(75887)\"\" \"About 
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Find the value of x in degree 5 (sin ^2)x + 12 sin x + 4 = 0
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\n" ); document.write( "5sin^2(x) + 12sin(x) + 4 = 0
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\n" ); document.write( "Factor:
\n" ); document.write( "5sin^2(x) + 10sin(x)+2sin(x) + 4 = 0
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\n" ); document.write( "5sin(x)[sin(x)+2][2((sin(x)+2)] = 0
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\n" ); document.write( "(sin(x)+2)(5sin(x)+2] = 0
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\n" ); document.write( "sin(x) = -2 (extraneous)
\n" ); document.write( "sin(x) = -2/5 = -0.4
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\n" ); document.write( "Ans: x = arcsin(-0.4) = -23.58 degrees or 180+23.58 degrees
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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