document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=72336>Question 72336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following 2 x 2 systems using substitutions<BR>\n" );
document.write( "2x + 7y =9<BR>\n" );
document.write( "9x + 4y =13 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51694 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51694\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2X+7Y=9, 2X=-7Y+9, X=-7Y/2+9/2, X=-3.5Y+4.5 NOW SUBSTITUTE IN THE OTHER EQUATION<BR>\n" );
document.write( "9(-3.5Y+4.5)+4Y=13<BR>\n" );
document.write( "-31.5Y+40.5+4Y=13<BR>\n" );
document.write( "-27.5Y=13-40.5<BR>\n" );
document.write( "-27.5Y=-27.5<BR>\n" );
document.write( "Y=-27.5/-27.5<BR>\n" );
document.write( "Y=1 ANSWER. NOW SOLVE FOR X<BR>\n" );
document.write( "2X+7*1=9<BR>\n" );
document.write( "2X=9-7<BR>\n" );
document.write( "2X=2<BR>\n" );
document.write( "X=2/2<BR>\n" );
document.write( "X=1 ANSWER.<BR>\n" );
document.write( "-------------------------------------------------------------------<BR>\n" );
document.write( "THIS IS THE METHOD. NOW GIVE IT A SHOT ON YOUR OWN FOR THE REST. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );