document.write( "Question 72294: If a piece of real estate purchased for $75,000 in 1998 appreciates at
\n" ); document.write( "the rate of 6% per year, then its value t years after the purchase will
\n" ); document.write( "be f (t) = 75,000(1 + .06t ) . According to this model, by how much will the
\n" ); document.write( "value of this piece of property increase between the years 2005 and
\n" ); document.write( "2008?
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Algebra.Com's Answer #51693 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Sometime in 1999, one year after purchase, the house has appreciated by
\n" ); document.write( "6%. By the formula, in 2005, 7 years after purchase, the house is worth
\n" ); document.write( "\"75000%281+%2B+.06t%29\"
\n" ); document.write( "\"75000%281+%2B+.06%2A7%29\"
\n" ); document.write( "In 2008, 10 years after purchase, the value is
\n" ); document.write( "\"75000%281+%2B+.06%2A10%29\"
\n" ); document.write( "Between those years it has appreciated
\n" ); document.write( "\"75000%281+%2B+%28.06%2A10%29%29+-+%2875000%281+%2B+%28.06%2A7%29%29%29\"
\n" ); document.write( "\"75000+%2B+.6%2A75000+-+75000+-+.42%2A75000\"
\n" ); document.write( "\".18%2A75000\"
\n" ); document.write( "\"13500\" answer
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