document.write( "Question 857886: In a sequence of 6 numbers every number after the first two is the average of the previous two numbers \r
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document.write( "The fourth number in the sequence is 22 and the 6th number is 45.\r
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document.write( "Determine all six numbers in the sequence. \n" );
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Algebra.Com's Answer #516921 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! We can immediately tell that the equation for the fifth number (E) is: \n" ); document.write( " \n" ); document.write( "Therefore, E + 22 = 90; E = 68 \n" ); document.write( "Our sequence looks like this: \n" ); document.write( "A, B, C, 22, 68, 45 \n" ); document.write( "Let's work backward to find C. \n" ); document.write( " \n" ); document.write( "C + 22 = 136 \n" ); document.write( "C = 114 \n" ); document.write( "Now we have: \n" ); document.write( "A, B, 114, 22, 68, 45 \n" ); document.write( "22 is the average of 114 and B. \n" ); document.write( "44 = 114 + ? \n" ); document.write( "B = -70 \n" ); document.write( "Now we have: \n" ); document.write( "A, -70, 114, 22, 68, 45 \n" ); document.write( "What is A? \n" ); document.write( "A + (-70) = 114*2, or 228 \n" ); document.write( "A = 298 \n" ); document.write( "Sequence is: \n" ); document.write( "298, -70, 114, 22, 68, 45 \n" ); document.write( ". \n" ); document.write( "Let make sure that works. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Success! \n" ); document.write( " \n" ); document.write( " |