document.write( "Question 857905: I paid my bill of $3.75using only coins. I used three times as many dimes as quarters and five more nickels than dimes. How many of each coin did I use? \n" ); document.write( "
Algebra.Com's Answer #516906 by stanbon(75887)\"\" \"About 
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I paid my bill of $3.75using only coins. I used three times as many dimes as quarters and five more nickels than dimes.
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\n" ); document.write( "d = 3q
\n" ); document.write( "n = d + 5
\n" ); document.write( "5n + 10d + 25q = 375 cents
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\n" ); document.write( "Substitute for \"q\" and for \"n\" and solve for \"d\";;;
\n" ); document.write( "5(d+5) + 10d + 25(d/3) = 375
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\n" ); document.write( "5d + 25 + 10d + (25/3)d = 375
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\n" ); document.write( "15d + (25/3)d = 350
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\n" ); document.write( "Multiply thru by 3 to get:
\n" ); document.write( "45d + 25d = 1050
\n" ); document.write( "70d = 1050
\n" ); document.write( "d = 15 (# of dimes)
\n" ); document.write( "q = d/3 = 5 (# of quarters)
\n" ); document.write( "n = d+5 = 30 (# of nickels)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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