document.write( "Question 857823: Total matterials used is 1.3m^2
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document.write( "Diamitar 36cm\r
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document.write( "I need the total height of a cylindar (punching bag) style.\r
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Algebra.Com's Answer #516870 by Alan3354(69443) You can put this solution on YOUR website! Total matterials used is 1.3m^2 \n" ); document.write( "Diamitar 36cm\r \n" ); document.write( "\n" ); document.write( "I need the total height of a cylindar (punching bag) style. \n" ); document.write( "================== \n" ); document.write( " \n" ); document.write( "Vol = 1.3 (cubic meters, not m^2) \n" ); document.write( "Vol = 1300 liters = 1300000 cc \n" ); document.write( "r = 18 cm \n" ); document.write( "----- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "h =~ 1293 cm = 12.93 meters \n" ); document.write( "-------------------------------- \n" ); document.write( "If you mean 1.3m^2 surface area: \n" ); document.write( "1.3 m^2 = 13000 cm^2 \n" ); document.write( "Each end is \n" ); document.write( "2 ends --> 2035.74 \n" ); document.write( "--- \n" ); document.write( "Lateral area = 2*pi*r*h = 36pi*h = 13000 - 2035.74 \n" ); document.write( "h = 10964/(36 pi) \n" ); document.write( "h =~96.95 cm = 0.97 meters\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |