document.write( "Question 857823: Total matterials used is 1.3m^2
\n" ); document.write( "Diamitar 36cm\r
\n" ); document.write( "\n" ); document.write( "I need the total height of a cylindar (punching bag) style.\r
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Algebra.Com's Answer #516870 by Alan3354(69443)\"\" \"About 
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Total matterials used is 1.3m^2
\n" ); document.write( "Diamitar 36cm\r
\n" ); document.write( "\n" ); document.write( "I need the total height of a cylindar (punching bag) style.
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\n" ); document.write( "\"Vol+=+pi%2Ar%5E2%2Ah\"
\n" ); document.write( "Vol = 1.3 (cubic meters, not m^2)
\n" ); document.write( "Vol = 1300 liters = 1300000 cc
\n" ); document.write( "r = 18 cm
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\n" ); document.write( "\"1300000+=+pi%5E18%5E2%2Ah\"
\n" ); document.write( "\"h+=+1300000%2F%28324%2Api%29\"
\n" ); document.write( "h =~ 1293 cm = 12.93 meters
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\n" ); document.write( "If you mean 1.3m^2 surface area:
\n" ); document.write( "1.3 m^2 = 13000 cm^2
\n" ); document.write( "Each end is \"pi%2Ar%5E2+=+324pi\" cm^2 =~ 1017.87 cm^2
\n" ); document.write( "2 ends --> 2035.74
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\n" ); document.write( "Lateral area = 2*pi*r*h = 36pi*h = 13000 - 2035.74
\n" ); document.write( "h = 10964/(36 pi)
\n" ); document.write( "h =~96.95 cm = 0.97 meters\r
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